Answer:
Both wires repels to each other and magnitude of the magnetic force between them is [tex]4.8 \times 10^{-5}[/tex] N
Explanation:
Given:
Current [tex]I =2[/tex] A
Length of wire [tex]l = 0.30[/tex] m
Separation between two wire [tex]a = 5 \times 10^{-3}[/tex] m
Here current is in opposite direction so both wires repels to each other.
Force in current carrying wire is given by,
[tex]F = \frac{\mu_{o} I^{2} l }{2\pi a}[/tex]
Where [tex]\mu_{o} = 4\pi \times 10^{-7}[/tex]
[tex]F = \frac{4\pi \times 10^{-7} \times (2)^{2} \times 0.3 }{2\pi \times 5 \times 10^{-3} }[/tex]
[tex]F = 4.8 \times 10^{-5}[/tex] N
Therefore, both wires repels to each other and magnitude of the magnetic force between them is [tex]4.8 \times 10^{-5}[/tex] N
