Answer: The osmotic pressure of a solution is 53.05 atm
Explanation:
To calculate the concentration of solute, we use the equation for osmotic pressure, which is:
[tex]\pi=iMRT[/tex]
Or,
[tex]\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT[/tex]
where,
[tex]\pi[/tex] = osmotic pressure of the solution = ?
i = Van't hoff factor = 1 (for non-electrolytes)
Mass of solute (methanol) = 22.3 g
Volume of solution = 321 mL
R = Gas constant = [tex]0.0821\text{ L.atm }mol^{-1}K^{-1}[/tex]
T = temperature of the solution = [tex]25^oC=[273+25]=298K[/tex]
Putting values in above equation, we get:
[tex]\pi=1\times \frac{22.3\times 1000}{32.04\times 321}\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K[/tex]
[tex]\pi=53.05atm[/tex]
Hence, the osmotic pressure of a solution is 53.05 atm
