Respuesta :
Answer:
Total moles of ions are released in water are [tex]1.131\times 10^{-5} mol[/tex].
Explanation:
Mass of calcium nitrate = [tex]6.18\times 10^{-4} g[/tex]
Molar mass of calcium nitrate = 164 g/mol
Moles of calcium nitrate = [tex]\frac{6.18\times 10^{-4} g}{164 g/mol}=3.77\times 10^{-6} mol[/tex]
[tex]Ca(NO_3)_2(aq)\rightarrow Ca^{2+}(aq)+2NO_3^{-}(aq)[/tex]
According to reaction, 1 mole of calcium nitrate gives 1 mole of calcium ions, then [tex]3.77\times 10^{-6}[/tex] moles of calcium nitrate will give:
[tex]1\times 3.77\times 10^{-6} mol=3.77\times 10^{-6} mol[/tex] of calcium ions
According to reaction, 1 mole of calcium nitrate gives 2 mole of nitrate ions, then [tex]3.77\times 10^{-6}[/tex] moles of calcium nitrate will give:
[tex]2\times 3.77\times 10^{-6} mol=7.54\times 10^{-6} mol[/tex] of nitrate ions
Total moles of ions are released :
[tex]3.77\times 10^{-6} mol+7.54\times 10^{-6} mol=11.31\times 10^{-6} mol\approx 1.131\times 10^{-5} mol[/tex]
