Answer:
Hence, correct answer is option A.
Explanation:
Mass of calcium carbonate = 3.25 g
Moles of calcium carbonate =[tex]\frac{3.25 g}{100 g/mol}=0.0325 mol[/tex]
[tex]2 HNO_3(aq) + CaCO_3(s)\rightarrow H_2O(l) + CO_2(g) + Ca(NO_3)_2(aq)[/tex]
According to reaction, 1 mole of calcium carbonate reacts with 2 moles of nitric acid then 0.0325 moles of calcium carbonate will react with :
[tex]\frac{2}{1}\times 0.0325 mol=0.0650 mol[/tex]
Moles of nitric acid = 0.0650 mol
Volume of the nitric acid solution = V
Molarity of the nitric solution = 0.300 M
[tex]Molarity=\frac{Moles}{Volume (L)}[/tex]
[tex]0.300 M=\frac{0.0650 M}{V}[/tex]
[tex]V=\frac{0.0650 mol}{0.300 M}=0.216 L[/tex]
1 L = 1000 mL
0.216 L = 0.216 × 1000 mL = 216 mL
Hence, correct answer is option A.
