Respuesta :
The diameter of the tuna fish is 5.048 inches, If it has a volume of 66 inches and a height of 3.3 inches.
Step-by-step explanation:
The given is,
A volume of tuna fish is 66 inches
Height of tuna fish is 3.3 inches
Step:1
Let, V - Volume of the tuna fish
h - Height of tuna fish
Where,
V - 66 cubic inches
h - 3.3 inches
Step:2
Formula to calculate the area is,
Area, [tex]A = \frac{Volume}{Height}[/tex]
= [tex]\frac{66}{3.3}[/tex]
A = 20 square inches
Step:3
Formula to calculate the radius,
Radius, [tex]r^{2} = \frac{A}{\pi }[/tex]
[tex]r^{2}[/tex] = [tex]\frac{20}{3.14}[/tex]
r = [tex]\sqrt{6.36943}[/tex]
r = 2.524 inches
Step:4
Formula to calculate the diameter,
[tex]d=2r[/tex]
= 2 × 2.524
d = 5.048 inches
Result:
Thus the diameter of the tuna fish is 5.048 inches, If it has a volume of 66 inches and a height of 3.3 inches.
