The simplification of the given expression will be "[tex]\frac{(x+3)}{x}[/tex]".
Given expression is:
→ [tex]\frac{x^2-9}{x^2-3x}[/tex]
By solving the brackets, we get
→ [tex]\frac{(x-3)(x+3)}{x^2-3x}[/tex]
∴ [tex]x^2-b^2=(a+b)(a-b)[/tex]
By taking "x" as a common, we get
→ [tex]\frac{(x-3)(x+3)}{x(x-3)}[/tex]
By cancelling the same elements, we get
→ [tex]\frac{(x+3)}{x}[/tex]
Thus the above answer is right.
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