Answer:
A
The current through the solution is [tex]I =35.61mA[/tex]
B
The current is moving from B to A
Explanation:
From the question we are told that
The number of [tex]Cl^{-}[/tex] that move from A to B is [tex]N_{cl} = 5.02 *10^{18} ions[/tex]
The time taken to move from A to B [tex]t_{cl} = 0.620[/tex]
[tex]=37.2 s[/tex]
Since the value of 1 charge is [tex]q =1.602 *10^{-19} C[/tex]
The quantity of charge Q that flow from A to B is mathematically given as
[tex]Q_{cl} = 5.02 *10^{18} * 1.602*10^{-19}[/tex]
[tex]=0.804C[/tex]
The number of [tex]Ca^{+}[/tex] that move from A to B is [tex]N_{ca} = 3.25*10^{18} ions[/tex]
Since time taken to move from A to B is equal to time taken to move from B to A [tex]t =t_{cl} =t_{ca}= 0.620=37.2s[/tex]
The quantity of charge Q that flow from B to A is mathematically given as
[tex]Q_{ca} = 3.25 *10^{18} * 1.602*10^{-19}[/tex]
[tex]=0.5207C[/tex]
The total quantity of charge is
[tex]Q_{tot}=Q_{cl} + Q_{ca}[/tex]
[tex]Q_{tot}= 0.804 + 0.5207[/tex]
[tex]= 1.325C[/tex]
The current flowing through the solution is
[tex]I =\frac{Q_{tot}}{t}[/tex]
[tex]I = \frac{1.325}{37.2}[/tex]
[tex]= 0.03561A[/tex]
[tex]I =35.61mA[/tex]
The flow is from B to A cause current flow from the positive terminal to negative terminal
