Answer:
[tex]1.4\times 10^{-13} Nm[/tex]
Explanation:
We are given that
Charge,q=[tex]3.5\times 10^{-15} C[/tex]
Distance, d=[tex]100\mu C=100\times 10^{-6} C[/tex]
[tex]1\mu C=10^{-6}C[/tex]
Electric field,E=[tex]4\times 10^5N/C[/tex]
We have to find the maximum possible torque on a sphere .
Electric dipole moment=qd
Using the formula
Electric dipole moment,p=[tex]3.5\times 10^{-15}\times 100\times 10^{-6} Cm[/tex]
Maximum torque,[tex]\tau=pE[/tex]
Using the formula
Torque,[tex]\tau==3.5\times 10^{-15}\times 100\times 10^{-6}\times 4\times 10^5[/tex]
[tex]\tau=1.4\times 10^{-13} Nm[/tex]
Hence, the maximum torque,[tex]\tau=1.4\times 10^{-13} Nm[/tex]