Answer:
t=0.21
Step-by-step explanation:
Given [tex]\bar x=69.2, s=10.9, n=125[/tex]and a population mean [tex]\mu=69[/tex].
#We state our hypothesis as:
[tex]H_o:\mu=69\\\\H_a:\mu\neq 69[/tex]
The evidence available should validate either the null or alternative hypothesis.
#We calculate the test statistic as:
[tex]t=\frac{\bar x-\mu_}{s/\sqrt{n}}\\\\\\=\frac{69.2-69}{10.9/\sqrt{125}}\\\\\\=0.2051[/tex]
[tex]\approx0.21[/tex]
Hence, the test statistic is t=0.21
