Answer:
736 N
Step-by-step explanation:
The dimensions of the rectangular tile are:
Length = 2.3m
Width = 1.6m
The pressure exerted on a surface is given by the formula
[tex]p=\frac{F}{A}[/tex]
where
p is the pressure
F is the force exerted
A is the area on which the force is exerted
In this problem, we have:
[tex]p=200 N/m^2[/tex] is the maximum pressure that the tile is able to sustain
A is the area of the tile, which can be calculated as the product between length and width, so:
[tex]A=L\cdot w =(2.3)(1.6)=3.68 m^2[/tex]
Re-arranging the formula for F, we can find the maximum force that can be safely applied to the tile:
[tex]F=pA=(200)(3.68)=736 N[/tex]
The maximum force is required.
The maximum force that can be safely applied is 740 N.
[tex]P[/tex] = Pressure = [tex]200\ \text{N/m}^2[/tex]
[tex]A[/tex] = Area of tile = [tex]1.6\times 2.3=3.68\approx 3.7\ \text{m}^2[/tex]
The dimensions of the tile have been assumed as they are not given.
[tex]F[/tex] = Force
Pressure is given by
[tex]P=\dfrac{F}{A}\\\Rightarrow F=PA\\\Rightarrow F=200\times 3.7\\\Rightarrow F=740\ \text{N}[/tex]
The maximum force that can be safely applied is 740 N.
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