Fig 1 : Perimeter = 30 unit and area = 40 sq unit
Fig 2 : Perimeter = 34 unit and area = 30 sq unit
Fig 3 : Perimeter = 42 unit and area = 70 sq unit
Fig 4 : Perimeter = 24 unit and area = 12 sq unit
Step-by-step explanation:
Given,
Fig 1 : Right angle triangle:
Base (b) = 10
Height (h) = 8
Hypotenuse (H) = 12
Fig: 2 Parallelogram:
Length (l) = 11
Width (b) = 6
Height (h) = 5
Fig 3 : Right angle triangle:
Base (b) = 10
Height (h) = 14
Hypotenuse (H) = 18
Fig: 4 Parallelogram:
Length (l) = 8
Width (b) = 4
Height (h) = 3
To find the area and perimeter of all the fig.
Formula:
Perimeter of right angle triangle = sum of all the sides
Area of right angle triangle = [tex]\frac{1}{2} bh[/tex]
Perimeter of parallelogram = 2(l+b)
Area of parallelogram = [tex]bh[/tex]
Now,
Fig 1 : Right angle triangle:
Perimeter of right angle triangle = 10+12+8 = 30 unit
Area of right angle triangle = [tex]\frac{1}{2}[/tex]×8×10 = 40 sq unit
Fig: 2 Parallelogram:
Perimeter of parallelogram = 2(11+6) = 34 unit
Area of parallelogram = 6×5 = 30 sq unit
Fig 3 : Right angle triangle:
Perimeter of right angle triangle = 10+14+18 = 42 unit
Area of right angle triangle = [tex]\frac{1}{2}[/tex]×14×10 = 70 sq unit
Fig: 4 Parallelogram:
Perimeter of parallelogram = 2(8+4) = 24 unit
Area of parallelogram = 6×5 = 30
Area of parallelogram = 4×3 = 12 sq unit
