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A big box of sausages (30 kg) is lifted from the ground to the top shelf of the freezer. If the box is lifted at a constant speed, a distance of 1.75 m, what work is done against gravity?

Respuesta :

Answer:

Work done to lift the box is 515.03 J

Explanation:

By work energy theorem we know that work done by all forces is equal to change in kinetic energy

So we have

[tex]W_g + W_{ex} = \Delta K[/tex]

so we have

[tex]-mgh + W_{ex} = 0[/tex]

so we have

[tex]W_{ex} = mgh[/tex]

[tex]W_{ex} = 30(9.8)1.75[/tex]

[tex]W_{ex} = 515.03 J[/tex]

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