Respuesta :
Answer:
1. 2C6H14 + 19O2 —> 12CO2 + 14H2O
2. 16.42g
Explanation:
1. We'll begin by balancing the equation. This is illustrated below:
C6H14 + O2 —> CO2 + H2O
There are 6 atoms of C on the left side and 1 atom on the right. It can be balance by putting 6 in front of CO2 as shown below:
C6H14 + O2 —> 6CO2 + H2O
There are 14 atoms of H on the left side and 2 atoms on the right. It can be balance by putting 7 in front of H2O as shown below:
C6H14 + O2 —> 6CO2 + 7H2O
Now, there are a total of 19 atoms of O on the right side and 2 at on the left side. It can be balance by putting 19/2 in front of O2 as shown below:
C6H14 + 19/2O2 —> 6CO2 + 7H2O
Now multiply through by 2 to clear the fraction as shown below:
2C6H14 + 19O2 —> 12CO2 + 14H2O
Now the equation is balanced
2. 2C6H14 + 19O2 —> 12CO2 + 14H2O
Let us determine the mass of C6H14 that reacted and the mass of CO2 produced from the balanced equation.
This is illustrated below:
Molar Mass of C6H14 = (12x6) + (14x1) = 72 + 14 = 86g/mol
Mass of C6H14 from the balanced equation = 2 x 86 = 172g
Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol
Mass of CO2 from the balanced equation = 12 x 44 = 528g
From the equation above,
172g of C6H14 produced 528g of CO2.
Therefore, 5.35g of C6H14 will produce = (5.35 x 528)/172 = 16.42g of CO2.
From the calculations made above, 16.42g of CO2 will be produced from 5.35g of C6H14
Answer:
16.4 grams of Carbon dioxide (CO2) gas will be formed
2C6H14(g) + 19O2(g) --> 12CO2(g) + 14H2O (g)
Explanation:
Step 1: Data given
Mass of C6H14 = 5.35 grams
Molar mass C6H14 = 86.18 g/mol
Molar mass CO2 = 44.01 g/mol
Step 2: The unbalanced equation
C6H14(g) + O2(g) --> CO2(g) + H2O (g)
Step 3: The balanced equation
2C6H14(g) + 19O2(g) --> 12CO2(g) + 14H2O (g)
Step 4: Calculate moles hexane (C6H14)
Moles hexane = mass hexane / molar mass hexane
Moles hexane = 5.35 grams / 86.18 g/mol
Moles hexane = 0.0621 moles
Step 5: Calculate moles CO2
For 2 moles hexane we need 19 moles oxygen to produce 12 moles carbon dioxide and 14 moles water
For 0.0621 moles hexane we'll have 6*0.0621 = 0.3726 moles CO2
Step 6: Calculate mass CO2
Mass CO2 = 0.3726 moles * 44.01 g/mol
Mass CO2 = 16.4 grams
16.4 grams of Carbon dioxide (CO2) gas will be formed
