The force between the charges is 60.47N
Explanation:
Given:
Charge, q₁ = 2.5 X 10⁻⁶ C
q₂ = 4.3 X 10⁻⁶ C
Distance, r = 0.04m
Force, F = ?
According to Coulomb's law:
[tex]F = k\frac{q_1q_2}{r^2}[/tex]
where,
k = Coulomb's constant
and the value of k is 9 X 10⁹ Nm²/C²
On substituting the value we get:
[tex]F = 9 X 10^9X\frac{2.5 X 10^-^6 X 4.3 X 10^-^6}{(0.04)^2} \\\\F = 60.47N[/tex]
Therefore, the force between the charges is 60.47N
