jbdoodlebug43 jbdoodlebug43
  • 04-07-2016
  • Mathematics
contestada

1^2 + 4^2 + 7^2 + ... + (3n - 2)^2 = n(6n^2-3n-1)/2

Respuesta :

jhonyy9
jhonyy9 jhonyy9
  • 04-07-2016
use math induction proof method will be usefully 

for n=1 will get 

1^2 = 1(6*1^2 -3*1 -1)/2
1 = 1(6-4)/2
1 = 1(2)/2
1 = 1

suppose true for n=k and prove for k = k+1 

hope this will help you 
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