Answer:
a) 2.4×10^4N/C
b) 2.9 ×10^3V
Explanation:
Correct ststement: An electric force of 3.9×10^-15N acts on the electron if it is placed anywhere between the two plates.
a) The electric field magnitude is given by E= F/e
Where F = electric force
e= elementary charge carried by a single proton e= 1.6×10^-19C
E= (3.9×10^-15)/(1.6×10^-19)
E= 2.4×10^4NC
b) Ptential difference is given by:
Change in V= E×change in distance
Potential difference= (2.4×10^4)× (0.12)
Potential difgerence= 2.9×10^3V
