Respuesta :
Answer:
Step-by-step explanation:
There are three bags
Bag A
2apples and 4 oranges
P(A¹)=2/6
P(A¹)=⅓
P(O¹)=4/6
P(O¹)=⅔
Bag B
8 apples and 4 oranges
P(A²)=8/12
P(A²)=⅔
P(O²)=4/12
P(O²)=⅓
Bag C
1 apple and 3 oranges
P(A³)=¼
P(O³)=¾
Note
P(A¹) means probability of Apple in bag A
P(A²) means probability of Apple in bag B
P(A³) means probability of Apple in bag C
P(O¹) means probability of oranges in bag A.
P(O²) means probability of oranges in bag B.
P(O³) means probability of oranges in bag C.
a. The probability of picking exactly two apples can be analyzed as
Picking apple in bag A and picking apple in bag B and picking orange in bag C or picking apple in bag A and picking orange in bag B and picking apple in bag C or picking orange in bag A and picking apple in bag B and picking apple in bag C.
Then,
P(exactly two apples)=P(A¹ n A² n O³) + P(A¹ n O² n A³) + P(O¹ n A² n A³)
Since they are mutually exclusive
Then,
P(exactly two apples) =
P(A¹) P(A²)P(O³) + P(A¹)P(O²)P(A³) + P(O¹) P(A²) P(A³)
P(exactly two apples) =
(⅓×⅔×¾)+(⅓×⅓×¼)+(⅔×⅔¼)
P(exactly two apples)=1/6 +1/36 +1/9
P(exactly two apples)= 11/36
b. Probability that an apple comes from Bag A out of the two apple will be Picking apple in bag A and picking apple in bag B and picking orange in bag C or picking apple in bag A and picking orange in bag B and picking apple in bag C.
P(an apple belongs to bag A)=P(A¹ n A² n O³) + P(A¹ n O² n A³)
Since they are mutually exclusive
Then,
P(an apple belongs to bag A) =
P(A¹) P(A²)P(O³) + P(A¹)P(O²)P(A³)
P(an apple belongs to bag A) =
(⅓×⅔×¾)+(⅓×⅓×¼)
P(an apple belongs to bag A)=1/6 +1/36
P(an apple belongs to bag A)= 7/36