Respuesta :

Answer:

The solution of the equation is [tex]x=\pm2\sqrt{6}=\pm 4.89[/tex].

Step-by-step explanation:

Given : Quadratic equation [tex]12x^2-288=0[/tex]

To find : Solve the quadratic equation using the square root method ?

Solution :

Quadratic equation [tex]12x^2-288=0[/tex]

Adding 288 both side,

[tex]12x^2-288+288=0+288[/tex]

[tex]12x^2=288[/tex]

Divide both side by 12,

[tex]\frac{12x^2}{12}=\frac{288}{12}[/tex]

[tex]x^2=24[/tex]

Taking square root both side,

[tex]\sqrt{x^2}=\pm\sqrt{24}[/tex]

[tex]x=\pm2\sqrt{6}[/tex]

or [tex]x=\pm 4.89[/tex]

Therefore, the solution of the equation is [tex]x=\pm2\sqrt{6}=\pm 4.89[/tex].