Answer:
The solution of the equation is [tex]x=\pm2\sqrt{6}=\pm 4.89[/tex].
Step-by-step explanation:
Given : Quadratic equation [tex]12x^2-288=0[/tex]
To find : Solve the quadratic equation using the square root method ?
Solution :
Quadratic equation [tex]12x^2-288=0[/tex]
Adding 288 both side,
[tex]12x^2-288+288=0+288[/tex]
[tex]12x^2=288[/tex]
Divide both side by 12,
[tex]\frac{12x^2}{12}=\frac{288}{12}[/tex]
[tex]x^2=24[/tex]
Taking square root both side,
[tex]\sqrt{x^2}=\pm\sqrt{24}[/tex]
[tex]x=\pm2\sqrt{6}[/tex]
or [tex]x=\pm 4.89[/tex]
Therefore, the solution of the equation is [tex]x=\pm2\sqrt{6}=\pm 4.89[/tex].