Respuesta :
Answer:
Reactions, 2, 3 and 5 make precipitates
Explanation:
1. The halogens always make aqueous salts with elements from group 1
2. Phosphate anion can make insoluble salts, the same as carbonate.
3. Nitrate anion always make aqueous salts
4. Sulfate anion makes aqueous salts except with Ag⁺, Pb⁺² and group 2
1. KI(aq) + NaCl(aq) → KCl(aq) + NaI(aq)
2. 2Na₃PO₄ (aq) + 3CoCl₂(aq) → 6NaCl(aq) + Co₃(PO₄)₂(s) ↓
3. Na₂CO₃ (aq) + CuCl₂ (aq) → 2NaCl (aq) + CuCO₃ (s) ↓
4. 2LiNO₃ (aq) + Na₂SO₄ (aq) → Li₂SO₄ (aq) + 2NaNO₃(aq)
5. CrCl₂ (aq) + Li₂CO₃ (aq) → 2LiCl (aq) + Cr₂(CO₃)₂ (s) ↓
The reactions Na3PO4+CoCl2, Na2CO3+CuCl2 and CrCl2+Li2CO3 produce precipitates.
A precipitate is said to be formed when reaction of two aqueous solutions produces an insoluble product. The insoluble solid product separates from the solution and is called a precipitate.
The full reactions are written below;
- KI(aq) + NaCl(aq) ----> KCl(aq) + NaI(aq)
- 2Na3PO4(aq) + 3CoCl2(aq) ------> Co3(PO4)2(s) + 6NaCl(aq)
- Na2CO3(aq) + CuCl2(aq) -------> CuCO3(s) + 2NaCl(aq)
- 2LiNO3(aq) + Na2SO4(aq) -------> Li2(SO4)(aq) + 2NaNO3(aq)
- CrCl2(aq) + Li2CO3(aq) -------> CrCO3(s) + 2LiCl(aq)
Hence, the reactions;
- 2Na3PO4(aq) + 3CoCl2(aq) ------> Co3(PO4)2(s) + 6NaCl(aq)
- Na2CO3(aq) + CuCl2(aq) -------> CuCO3(s) + 2NaCl(aq)
- CrCl2(aq) + Li2CO3(aq) -------> CrCO3(s) + 2LiCl(aq)
Produce precipitates.
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