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Both portions of the rod ABC are made of an aluminum for whichE = 70 GPa. Knowing that the magnitude of P is 4 kN, determine(a) the value of Q so that the deflection at A is zero, (b) the correspondingdeflection of B.0.4 m0.5 m

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Memoona

Explanation:

Δ[tex]L_{BC}[/tex] = Δ[tex]L_{AB}[/tex]

[tex]\frac{(Q - 4000)(0.5)}{3.14* 0.03 *0.03 *70*10^{9} }[/tex]     (1)

= [tex]\frac{4000*0.4}{3.14*0.01*0.01*70*10^{9} }[/tex]

Q = 32,800 N

now put this value in equation 1.

Deflection of B = [tex]\frac{(32800-4000)(0.5)}{3.14*0.03*0.03*70*10^{9} }[/tex]

                       = 0.0728 mm

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