Answer:
[tex]\frac{31}{72}[/tex]
Step-by-step explanation:
Number of Blue(B) Chips=5
Number of Red(R) Chips=4
Number of Yellow(Y) Chips=3
Total Number of Chips=5+4+3=12
Pr(B)=5/12, Pr(R)=2/12, Pr(Y)=3/12
If two chips of different colors are selected one after the other with replacement, the following combinations are possible.
BR, BY, RB, RY, YB, YR
The probability that the two selected chips are of different colors
Pr(BR OR BY OR RB OR RY OR YB OR YR)=
[tex]=(5/12X2/12) + (5/12 X 3/12) + (2/12 X 5/12) +(2/12 X 3/12) + (3/12 X 5/12) + (3/12 X 2/12)[/tex]
=[tex]\frac{10}{144} +\frac{15}{144} +\frac{10}{144} +\frac{6}{144} +\frac{15}{144} + \frac{6}{144}[/tex]
=[tex]\frac{62}{144} =\frac{31}{72}[/tex]