Answer:
[tex]a=1.1*10^{18}\frac{m}{s^2}[/tex]
Explanation:
We use the following kinematic formula to calculate the acceleration:
[tex]v_f^2=v_0^2+2ax[/tex]
The kinetic energy is defined as:
[tex]\Delta K=\frac{m(v_f^2-v_0^2)}{2}\\v_f^2-v_0^2=\frac{2\Delta K}{m}[/tex]
Replacing this in the acceleration formula and solving for a:
[tex]\frac{2\Delta K}{m}=2ax\\a=\frac{\Delta K}{mx}\\a=\frac{2*10^{-18}J}{(9.1*10^{-31}kg)(2*10^{-6}m)}\\a=1.1*10^{18}\frac{m}{s^2}[/tex]
