Answer:
(εtrue/εengr) = (1.3481/2.85) = 0.473
This shows that the engineering strain is truly a bit far off the true strain.
Explanation:
εengr
Engineering strain is a measure of how much a material deforms under a particular load. It is the amount of deformation in the direction of the applied force divided by the initial length of the material.
ε(engineering) = ΔL/L₀
Lf = final length = 3.85 L₀
L₀ = original length = L₀
ΔL = Lf - L₀ = 3.85 L₀ - L₀ = 2.85 L₀
ε(engineering) = ΔL/L₀ = (2.85L₀)/L₀ = 2.85
εtrue
True Strain measures instantaneous deformation. It is obtained mathematically by integrating strain over small time periods and Running them up. Hence,
ε(true) = In (Lf/L₀)
Lf = 3.85L₀
L₀ = L₀
ε(true) = In (Lf/L₀) = In (3.85L₀/L₀) = In 3.85 = 1.3481
(εtrue/εengr) = (1.3481/2.85) = 0.473