Answer:
0.9500, 0.4407, 0.3904
Step-by-step explanation:
(a) P(x ≤ 60). We need to find the area under the standard normal curve to the left of x = 60. The appropriate command when using a TI-83 Plus calculator with statistical functions is normcdf(-1000, 60, 49, 6.7). This comes out to 0.9500. P(x ≤ 60) = 0.9500
(b) P(x ≥ 50) would be normcdf(50, 1000,49, 6.7), or 0.4407
(c) P(50 ≤ x ≤ 60) would be normcdf(50,60,49,6.70, or 0.3904