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At a recent audition school play, 1 out of 3 students who auditioned were asked to come to a second audition . After the second audition ,75% of those asked to the second audition were offered parts. If 18 students were offered parts , how many students were offered to the first audition

Respuesta :

Answer:

The total students appearing in first audition = 72

Step-by-step explanation:

As given in the question:

1 out of 3 students were asked to come for second audition.

Let us assume the TOTAL STUDENT who came to first audition =  m

So, [tex](\frac{1}{3}) m[/tex] appeared for the SECOND ROUND.

Now, 75% of students appearing in second audition were offered parts.

Calculating 75% of  [tex](\frac{1}{3}) m[/tex]

[tex]\frac{75}{100} \times\frac{1}{3} m = 0.25 m[/tex]

Also, as said 18 students were offered parts.

⇒ 0. 25 m = 18

Now, solving for m, we get:

m = 18/0.25  = 72

or, m = 72

Hence, the total students appearing in first audition = 72

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