Answer:
Shown below
Explanation:
a) for BrN3
80+3(14)=122amu
b) forC2H6
2(12) + 6(1) = 30amu
C) for NF2
14+2(19) = 52amu
D) Al2S3
2(27) + 3(32)= 150amu
E) for Fe(NO3)3
56 + 3 [14+3(16)] =242amu
F) Mg3N2
3(24) + 2(14)= 100amu
G) for (NH4)2CO3
2[14 +4(1)] +12 +3(16)=96amu
Answer:
Explanation:
The atomic unit of mass (a.m.u) is the unit used to compare the relative masses of atoms. An atomic mass unit is a twelfth of the mass of a carbon-12 atom.
The calculation of the molecular mass of a compound is done by adding the relative atomic masses of the atoms of the formula of said substance, taking into account its abundance in the compound. The atomic mass of the atoms that make up the molecule are obtained in the Periodic Table.
So, in these cases you have:
You know the atomic masses of the elements that make up the molecule, obtained from the periodic table:
Br: 79.9 amu
N: 14 amu
I take into account the abundance of each element in the compound you get:
BrN₃=79.9 amu + 3* 14 amu= 121.9 amu
You know the atomic masses of the elements that make up the molecule, obtained from the periodic table:
C: 12 amu
H: 1 amu
I take into account the abundance of each element in the compound you get:
C₂H₆= 2*12 amu + 6*1 amu= 30 amu
You know the atomic masses of the elements that make up the molecule, obtained from the periodic table:
N: 14 amu
F: 19 amu
I take into account the abundance of each element in the compound you get:
NF₂= 14 amu + 2*19 amu= 52 amu
You know the atomic masses of the elements that make up the molecule, obtained from the periodic table:
Al: 27 amu
S: 32 amu
I take into account the abundance of each element in the compound you get:
Al₂S₃= 2*27 amu + 3*32 amu= 150 amu
You know the atomic masses of the elements that make up the molecule, obtained from the periodic table:
Fe: 55.85 amu
N: 14 amu
O: 16 amu
I take into account the abundance of each element in the compound you get:
Fe(NO₃)₃= 55.85 amu + 3*(14 amu + 3*16 amu)= 241.85 amu
You know the atomic masses of the elements that make up the molecule, obtained from the periodic table:
N: 14 amu
Mg: 24 amu
I take into account the abundance of each element in the compound you get:
Mg₃N₂= 3*24 amu + 2*14 amu= 100 amu
You know the atomic masses of the elements that make up the molecule, obtained from the periodic table:
N: 14 amu
H: 1 amu
C: 12 amu
O: 16 amu
I take into account the abundance of each element in the compound you get:
(NH₄)₂CO₃: 2*(14 amu + 4*1 amu) + 12 amu+3*16 amu= 96 amu
