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Derek walks along a road which can be modeled by the equation y =2x, where (0,0) represents his starting point. When he reaches the point (7, 14), he turns right, so that he is traveling perpendicular to the original road, until he stops at a point which is due east of his starting point (in other words, on the x-axis). What is the point where Derek stops? Select the correct answer below: (39,0) (38, 0) (31,0) (29, 0) (35, 0) (30,0)

Respuesta :

Answer:

(35,0)

Step-by-step explanation:

Consider the diagram below, the starting point is given as A and the finish point given as C.

Using similar right-angle triangle, we have that:

[tex]\frac{|AM|}{|BM|}= \frac{|BM|}{|MC|}\\\frac{7}{14}= \frac{14}{x}\\7x=14 X 14\\x=196/7=28[/tex]

Therefore to find the point where Derek stops at C, we first determine the distance |AC|

|AC|=7+28=35

The Coordinates at C where Derek stops is (35,0)

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