Answer:
a. 0.0312 or 3.12%
b. 0.024 or 2.40%
Step-by-step explanation:
a. The probability that randomly selected child has at least one food allergy and a history of severe reaction is determined by the probability of having a food allergy (8%) multiplied by the probability of having a history of severe reaction (39%):
[tex]P = 0.08*0.39\\P=0.0312 = 3.12\%[/tex]
b. The probability that randomly selected child is allergic to multiple foods is determined by the probability of having a food allergy (8%) multiplied by the probability of being allergic to multiple foods (30%):
[tex]P = 0.08*0.30\\P=0.024 = 2.40\%[/tex]