2.61 kilojoules of heat would be liberated by the condensation of 5.00 g of acetone
Explanation:
To convert grams into moles
[tex]moles = grams \times \frac{1 mole}{grams}[/tex]
We have 5.00 g acetone
[tex]moles = 5 \times \frac{1}{58.1}[/tex]
[tex]moles = 0.0861[/tex]
Heat liberated = moles [tex]\times[/tex] heat of vapourization
=0.0861 mol x 30.3 kJ/mol
= 2.61 kJ
Therefore, 2.61 kilojoules of heat would be liberated by the condensation of 5.00 g of acetone
