The toothpick mass was 0.14 g, its speed before entering the branch was 218 m/s, and its penetration depth was 14 mm. If its speed was decreased at a uniform rate, what was the magnitude of the force of the branch on the toothpick

Respuesta :

Answer:

 = 238N

Explanation:

mass = 0.14g = 14 × 10⁻⁵kg

initial velocity = 218m/s

final velocity = 0

penetration depth (distance) = 14mm = 14 × 10⁻³m

v²(final) = v²(initial) + 2aΔx

0² = (218)² + 2(14 × 10⁻³)a

a = -(218)² /  2(14 × 10⁻³)

a = 16.97 × 10⁵m/s²

F = ma

 = (14 × 10⁻⁵)(16.97 × 10⁵)

 = 237.58N

 ≅ 238N

Explanation:

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