Answer : The volume of the balloon at STP is, 2.04 L
Explanation :
First we have to calculate the moles of dry ice.
[tex]\text{Moles of dry ice}=\frac{\text{Mass of dry ice}}{\text{Molar mass of dry ice}}[/tex]
Molar mass of dry ice [tex](CO_2)[/tex] = 44 g/mol
[tex]\text{Moles of dry ice}=\frac{4.00g}{44g/mol}=0.0909mol[/tex]
Now we have to calculate the volume of dry ice.
As we know that 1 mole of substance contains 22.4 L volume of gas.
As, 1 mole of dry ice contains 22.4 L volume of gas.
So, 0.0909 mole of dry ice contains 0.0909 × 22.4 L = 2.04 L volume of gas.
Thus, the volume of the balloon at STP is, 2.04 L