Answer:
The probability that the service desk will have at least 100 customers with returns or exchanges on a randomly selected day is P=0.78.
Step-by-step explanation:
With the weekly average we can estimate the daily average for customers, assuming 7 days a week:
[tex]M=756/7=108[/tex]
We can model this situation with a Poisson distribution, with parameter λ=108. But because the number of events is large, we use the normal aproximation:
[tex]P(\lambda)\approx N(\lambda,\lambda)[/tex]
Then we can calculate the z value for x=100:
[tex]z=\frac{x-\mu}{\sigma}=\frac{100-108}{\sqrt{108}}=\frac{-8}{10.4} =-0.77[/tex]
Now we calculate the probability of x>100 as:
[tex]P(x>100)=P(z>-0.77)=0.78[/tex]
The probability that the service desk will have at least 100 customers with returns or exchanges on a randomly selected day is P=0.78.