contestada

The random variable X, representing the number of accidents in a certain intersection in a week, has the following probability distribution: x 0 1 2 3 4 5 P(X = x) 0.20 0.30 0.20 0.15 0.10 0.05 On average, how many accidents are there in the intersection in a week? a. 5.3 b. 2.5 c. 1.8 d. 0.30 e. 0.1667

Respuesta :

Answer:

The average accidents in the intersection per week is 1.8                

Step-by-step explanation:

We are given the following in he question:

x:                0        1          2        3        4       5

P(X = x):  0.20   0.30   0.20   0.15   0.10   0.05

We have to find the number of average accidents per week.

Formula:

[tex]E(x) = \displaystyle\sum x_iP(x_1)\\E(x)=0(0.20)+ 1(0.30)+ 2(0.20)+ 3(0.15)+ 4(0.10) + 5(0.05)\\E(x) = 1.8[/tex]

Thus, the average accidents in the intersection per week is 1.8

Otras preguntas