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A high-speed dart is shot from ground level with a speed of 150 m/s at an angle 30° above the horizontal. What is the vertical component of its velocity after 4.0 s if air resistance is neglected?

Respuesta :

This vertical component of velocity is 35 m/s

Explanation:

The dart is project with 150 m/s from a point at an angle of 30⁰

The vertical component of velocity = 150 sin 30 = 75 m/s

Thus initial vertical velocity is = 75 m/s

The velocity after 4 s can be calculate by

v = u - g t

here u is the initial velocity and t is the time , g is the acceleration due to gravity .

Thus v = 75 - 10 x 4 = 35 m/s

Cricetus

The velocity after 4.0 seconds will be "35 m/s".

According to the question,

Speed,

  • 150 m/s

Angle,

  • 30°

Vertical component of velocity,

  • [tex]150 \ Sin 30^{\circ} = 75 \ m/s[/tex]

After 4 seconds, the velocity will be:

→ [tex]v = u-gt[/tex]

By substituting the values, we get

     [tex]= 75-10\times 4[/tex]

     [tex]= 75-40[/tex]

     [tex]= 35 \ m/s[/tex]

Thus the answer above is right.    

Learn more:

https://brainly.com/question/14755221

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