contestada

What is the critical angle θcritθcrittheta_crit for light propagating from a material with index of refraction of 1.50 to a material with index of refraction of 1.00?

Respuesta :

Answer:

The critical angle is 41.8°.

Explanation:

The critical angle is [tex]\theta_1[/tex] for which the angle of refraction [tex]\theta_2[/tex] is 90°. From Snell's law we have

[tex]n_1sin (\theta_1 ) = n_2 sin(\theta_2)[/tex]

[tex]n_1sin (\theta_1 ) = n_2 sin(90^o)[/tex]

[tex]sin (\theta_1 ) = n_2/n_1,[/tex]

[tex]\theta_1 = sin^{-1}(\dfrac{n_2}{n_1} ).[/tex]

Putting in [tex]n_2 =1.00,[/tex] and [tex]n_1 = 1.50[/tex] we get:

[tex]\theta_1 = sin^{-1}(\dfrac{1.00}{1.500} ),[/tex]

[tex]\boxed{\theta_1 = 41.8^o}[/tex]

Thus, the critical angle is 41.8°.

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