Solution:
The volume of a container varies jointly with the square of its radius, r, and its height, h
Therefore,
[tex]v \propto r^2 h\\\\v = k \times r^2h -------- eqn\ 1[/tex]
The container has a height of 10 centimeters, and radius of 6 centimeters, and a volume of 377 cubic centimeters
Substitute v = 377 and h = 10 and r = 6 in eqn 1
[tex]377 = k \times 6^2 \times 10\\\\377 = k \times 360\\\\k = 1.047 \approx 1.05[/tex]
What is the volume of a container with a radius of 4 centimeters and a height of 4 centimeters?
Substitute k = 1.05 and r = 4 and h = 4 in eqn 1
[tex]v = 1.05 \times 4^2 \times 4\\\\v = 1.05 \times 16 \times 4\\\\v = 67.2[/tex]
Thus volume of a container with a radius of 4 centimeters and a height of 4 centimeters is 67.2 cubic centimeter