Explanation:
The area of a trapezoid is given by:
[tex]A=\frac{(B_{1}+B_{2})h}{2} \\ \\ \\ A;Area \\ \\ B_{1}:First \ base \\ \\ B_{2}=Second \ base \\ \\ h:Heigth[/tex]
So given the equation:
[tex]\frac{( 12 + 14 )h}{2} = 52[/tex]
We can write a real problem as:
The bases of a trapezoid are [tex]12cm \ and \ 14cm[/tex] and the area of it is [tex]52cm^2[/tex]. What is the height of the trapezoid?
Solving:
[tex]\frac{( 12 + 14 )h}{2} = 52 \\ \\ 26h=104 \\ \\ h=\frac{104}{26} \\ \\ h=4cm[/tex]
Finally, the height of the trapezoid is 4cm
