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If ​x​ and ​y​ are positive integers and the mean of 4, 20, and ​x​ is equal to the mean of ​y​ and 16, what is the smallest possible value of ​x​ + ​y​?

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amna04352

Answer:

5

Step-by-step explanation:

(4+20+x)/3 = (y+16)/2

2(24+x) = 3(y+16)

48 + 2x = 3y + 48

2x = 3y

Since x and y are positive integers, they can't be 0. To satisfy 2x = 3y

We'll have to use LCM of 2 and 3, which is 6 (or a multiple of 6)

For the least value, we use 6

To make both sides 6,

x = 3 and y = 2

Hence x + y = 5

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