Answer:
12in long and 10in wide
Step-by-step explanation:
If he were to trim the edges of the photographs to [tex]12\frac{1}{2}[/tex] and [tex]10\frac{1}{2}[/tex], the edges of the photographs from Russ's vacation would be too long and wide to fit inside of the photo album.
If you convert the fractions into decimals, you can easily discern that the vacation photos would be too large to fit inside of the photo album.
Photo Album:
[tex]12\frac{1}{8}[/tex] = 12.1 inches •Original
[tex]10\frac{1}{8}[/tex] = 10.1 inches •Original
• Too large:
[tex]12\frac{1}{2}[/tex] = 12.5 inches > 12.1 - 12.5 = -0.4 •Too large
[tex]10\frac{1}{2}[/tex] = 10.5 inches > 10.1 - 10.5 = -0.4 •Too large
• Just right:
10 = 10 inches > 10.1 - 10 = 0.1 •Space left
12 = 12 inches > 12.1 - 12 = 0.1 •Space left
