Answer:
Hydrogen takes 0.391s to get to distance x
Explanation:
From the chromatography table:
[tex]D_H_2=6.4\times10^{-5}m^2/s\\D_O_2=1.8\times10^{-5}m^2/s\\[/tex]
Using the equation[tex]x_m_s=\sqrt(2Dt)[/tex]. This equation relates time to distance during diffusion
[tex]x_m_s[/tex],[tex]_O_2[/tex]=[tex]\sqrt[/tex][tex]2D_o_2[/tex][tex]t_o_2[/tex] and [tex]x_m_s[/tex],[tex]__H_2[/tex]=[tex]\sqrt[/tex][tex]2D_H__2[/tex][tex]t_H__2[/tex]
Let the distance traveled be denoted by x(same distance traveled by both gases).
Distance is same when difference between[tex]t_H__2[/tex] and [tex]t_O__2[/tex] is 1.0 seconds.
[tex]t_O__2=t_H___2[/tex][tex]+1.0s[/tex]
At equal distance=>
[tex]2D_O__2[/tex][tex]t_O__2[/tex]=[tex]2D_H__2[/tex][tex]t_H__2[/tex]
[tex]D_O_2[/tex][tex](t_H__2[/tex][tex]+1.0s)=D_H__2[/tex][tex]t_H__2[/tex]
Solving for hydrogen time:
[tex]t_H__2=(D_0__2)\div[/tex][tex](D_H__2[/tex]-[tex]D_O__2)[/tex][tex]\times1.0[/tex]
=[tex](1.8\times10^{-5}m^2/s)\div(6.4\times10^{-5}m^2/s-1.8\times10^{-5}m^2/s)\times1.0s[/tex]
=0.391s
