A farmer sold 20% of his chickens in the morning. He sold 240 chickens in the afternoon. He had 30% of his chickens left. How many chickens did the farmer have at first?

Respuesta :

Answer:

The afrmer had 480 chickens at first

Step-by-step explanation:

We make an assumption here, that the initial number of chickens that the farmer has, is C.

Chickens sold by the farmer is (20% of C) + 240 chickens

Number of chickens left after selling in the morning and afternoon is 30% of C

So, the first number of chickens = Number of chickens sold + Number of chickens left

This gives us an equation that will be solved to obtain C.

C = ([tex]\frac{20}{100}[/tex] × C) + 240 chickens + ([tex]\frac{30}{100}[/tex] × C) = 0.2C + 240 chickens + 0.3C

C = 0.5C + 240 chickens

C - 0.5C = 240 chickens

0.5C = 240 chickens

C = [tex]\frac{240 chickens}{0.5}[/tex]

C = 480 Chickens

Answer: the answer is C = 480

Step-by-step explanation: