Petroleum pollution in oceans stimulates the growth of certain bacteria. An assessment of this growth has been madew by counting the bacteria in each of 5 randomly chosen specimens of ocean water (of a fixed size). The 5 counts obtained were as follows.

41, 62, 45, 48, 69

Find the deviation of this sample of numbers. Round your answers to at least two decimal places.

Respuesta :

Answer:

The standard deviation for given sample is 11.94    

Step-by-step explanation:

We are given the following sample of count of bacteria:

41, 62, 45, 48, 69

Formula:

[tex]\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}[/tex]  

where [tex]x_i[/tex] are data points, [tex]\bar{x}[/tex] is the mean and n is the number of observations.  

[tex]Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}[/tex]

[tex]Mean =\displaystyle\frac{265}{5} = 53[/tex]

Deviation from mean:

-12, 9, -8, -5, 16

Sum of squares of differences =

144 + 81 + 64 + 25 + 256 = 570

[tex]s = \sqrt{\frac{570}{4}} = 11.94[/tex]

Thus, the standard deviation for given sample is 11.94