The graphics in the attachment is part of the question, which was incomplete.
Answer: Fr = 102N and angle of approximately 11°.
Explanation: From the attachment, it is observed that from the three forces acting on M, two are perpendicular. So to find them, we have to show their x- and y- axis components. From the graph:
Fx = 70+40-10 = 100
Fy = 40-20 = 20
Now, as the forces form a triangle, the totalforce is:
Fr = [tex]\sqrt{Fx^{2} +Fy^{2} }[/tex]
Fr = [tex]\sqrt{10400}[/tex]
Fr = ≈ 102N
To determine the angle requested, we use:
arctg H = [tex]\frac{Fy}{Fx}[/tex]
arctg H = [tex]\frac{20}{100}[/tex]
H = tg 0.2 ≈ 11°.
