Answer:
The answer to your question is 0.82 moles of CO₂
Explanation:
Data
V = 10L
T = 25°C
P = 1 atm
moles = n = ?
R = 0.08205 atm L/mol°K
Process
1.- Convert °C to °K
T = 25 + 273 = 298°K
2.- Use the ideal gas law to find the moles of Acetylene
PV = nRT
Solve for n
n = PV / RT
Substitution
n = (1)(10) / (0.08205)(298)
Simplification
n = 10 / 24.45
Result
n = 0.409 moles of Acetylene
3.- Use proportions to find the moles of CO₂
2 moles of C₂H₂ ------------------- 4 moles of CO₂
0.409 moles ------------------- x
x = (0.409 x 4) / 2
x = 1.636 / 2
x = 0.82 moles of CO₂