Marquises has 200 meters of fencing to build a rectangular garden. The gardens area (in square meters) as a function of the garden's width is (in meters) is modeled by A(W)=-w^2+100w What side width will produce the maximum garden area ?

Respuesta :

The width of 50 meter will produce the maximum garden area

Solution:

Given that,

[tex]A(w) = -w^2 + 100w[/tex]

Where, "w" is the width

Given area is in quadratic form

To find maximum area, we need to find the vertex

[tex]w = \frac{-b}{2a}[/tex]

From given quadratic,

[tex]-w^2 + 100w[/tex]

a = - 1

b = 100

Therefore,

[tex]w = \frac{-100}{2 \times -1}\\\\w = 50[/tex]

We will get maximum area when width w = 50 meters

To find maximum are we plug in 50 for w and find A(50)

[tex]A(50) = -(50)^2 + 100(50)\\\\A(50) = -2500 + 5000\\\\A(50) = 2500[/tex]

So maximum area is 2500 square meter

Answer:50

Step-by-step explanation: