Here in question, the table is not given to complete the table with ordered pairs. So, in general, found the possible integer ordered pairs to create the table as in attached figure are [tex](x,y) =(0,3), (12,0),(4,2),(8,1)[/tex].
Step-by-step explanation:
We have the following given linear equation : [tex]x+4y = 12[/tex].Let's find out ordered pairs that satisfies this linear equation .
At x=0 ,
[tex]0 + 4y = 12 \\4y=12\\y=3[/tex]
So, one pair is [tex](x,y) = (0,3)[/tex].
Similarly, At y=0,
[tex]x +4.0 = 12\\x=12[/tex]
SO, another pair is [tex](x,y) = (12,0)[/tex].
At x=4,
[tex]4+4y=12\\4y=8\\y=2[/tex]
Pair is [tex](x,y) = (4,2)[/tex].
At x=8,
[tex]8+4y=12\\4y=4\\y=1[/tex]
Pair is [tex](x,y) = (8,1)[/tex].
Therefore all the possible integer ordered pairs are [tex](x,y) =(0,3), (12,0),(4,2),(8,1)[/tex].
