The value of x is 15 and value of y is 18
Solution:
Given equations are:
[tex]\frac{2}{3}(x - 6) = 6\\\\\frac{2}{3}y - 6 = 6[/tex]
From first equation,
[tex]\frac{2}{3}(x - 6) = 6\\\\Remove\ the\ parenthesis\ and\ solve\\\\\frac{2}{3}x - \frac{2}{3} \times 6 = 6\\\\\frac{2}{3}x - 4 = 6\\\\Move\ the\ constant\ from\ left\ side\ to\ right\ side\\\\\frac{2}{3}x = 6 + 4\\\\\frac{2}{3}x= 10\\\\2x = 30\\\\Divide\ both\ sides\ by 2\\\\x = 15[/tex]
From second equation,
[tex]\frac{2}{3}y - 6 = 6\\\\Move\ the\ constant\ from\ left\ side\ to\ right\ side\ of\ equation\\\\\frac{2}{3}y = 6 + 6\\\\\frac{2}{3}y = 12\\\\2y = 36\\\\Divide\ both\ sides\ by\ 2\\\\y = 18[/tex]
Thus value of x is 15 and value of y is 18
