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(Remember: Use the final velocity formula) A vehicle is approaching a stop light. The vehicle slams on their
breaks and begins to decelerate at -2.5 m/s2. It takes the car 4 seconds to come to a near stop. The car had an
initial velocity of 12 m/s. Determine the car's final velocity.

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Onoriodefelix

Answer:

v = 2m/s

Explanation:

V = u + at

Where v = final velocity

u = initial velocity

a = acceleration

t = time

Given u = 12m/s

a = -2.5m/s^2

t = 4 secs

Therefore

v = 12 + (-2.5 x 4)

v = 12 + (-10)

Positive negative gives negative. So the positive sign changes to negative sign

v = 12 - 10

v = 2m/s

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