we know that
the equation of the circle is of the form
[tex] (x-h)^{2} +(y-k)^{2} =r^{2} [/tex]
where
(h,k) is the center of the circle
r is the radius of the circle
in this problem we have
[tex] (x+5)^{2} +(y-3)^{2} =4^{2} [/tex]
so
the center is the point [tex] (-5,3) [/tex]
the radius is [tex] 4\ units [/tex]
therefore
the answer is
The radius of the circle is equal to [tex] 4\ units [/tex]
