The distance between the points (2,3) and (5,5) is 3.6 units
Solution:
Distance between two points is given by:
[tex]d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}[/tex]
We have to find the distance in the standard (x, y) coordinate plane between the points (2,3) and (5,5)
From given,
[tex](x_1, y_1) = (2, 3)\\\\(x_2, y_2) = (5, 5)[/tex]
Substituting the values we get,
[tex]d = \sqrt{(5-2)^2 + (5-3)^2}\\\\Simplify\\\\d = \sqrt{3^2 + 2^2}\\\\d = \sqrt{9+4}\\\\d = \sqrt{13}\\\\In\ decimal\ form\\\\d = 3.605 \approx 3.6[/tex]
Thus distance between the points (2,3) and (5,5) is 3.6 units
